5*(t^2)-14*(t)+51=0

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Solution for 5*(t^2)-14*(t)+51=0 equation:


Simplifying
5(t2) + -14(t) + 51 = 0

Reorder the terms:
51 + -14t + 5t2 = 0

Solving
51 + -14t + 5t2 = 0

Solving for variable 't'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
10.2 + -2.8t + t2 = 0

Move the constant term to the right:

Add '-10.2' to each side of the equation.
10.2 + -2.8t + -10.2 + t2 = 0 + -10.2

Reorder the terms:
10.2 + -10.2 + -2.8t + t2 = 0 + -10.2

Combine like terms: 10.2 + -10.2 = 0.0
0.0 + -2.8t + t2 = 0 + -10.2
-2.8t + t2 = 0 + -10.2

Combine like terms: 0 + -10.2 = -10.2
-2.8t + t2 = -10.2

The t term is -2.8t.  Take half its coefficient (-1.4).
Square it (1.96) and add it to both sides.

Add '1.96' to each side of the equation.
-2.8t + 1.96 + t2 = -10.2 + 1.96

Reorder the terms:
1.96 + -2.8t + t2 = -10.2 + 1.96

Combine like terms: -10.2 + 1.96 = -8.24
1.96 + -2.8t + t2 = -8.24

Factor a perfect square on the left side:
(t + -1.4)(t + -1.4) = -8.24

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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